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1313402204113 = 5922261054307
BaseRepresentation
bin10011000111001100110…
…111110010111111010001
311122120010020221222000021
4103013030313302333101
5133004321431012423
62443211343223441
7163614221350636
oct23071467627721
94576106858007
101313402204113
1146701333853a
121926678a7b81
1396b128cca2c
14477d74d018d
152427082395d
hex131ccdf2fd1

1313402204113 has 4 divisors (see below), whose sum is σ = 1335663258480. Its totient is φ = 1291141149748.

The previous prime is 1313402204089. The next prime is 1313402204251. The reversal of 1313402204113 is 3114022043131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313402204113 - 237 = 1175963250641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313402234113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11130527095 + ... + 11130527212.

It is an arithmetic number, because the mean of its divisors is an integer number (333915814620).

Almost surely, 21313402204113 is an apocalyptic number.

It is an amenable number.

1313402204113 is a deficient number, since it is larger than the sum of its proper divisors (22261054367).

1313402204113 is an equidigital number, since it uses as much as digits as its factorization.

1313402204113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22261054366.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1313402204113 its reverse (3114022043131), we get a palindrome (4427424247244).

The spelling of 1313402204113 in words is "one trillion, three hundred thirteen billion, four hundred two million, two hundred four thousand, one hundred thirteen".

Divisors: 1 59 22261054307 1313402204113