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13134023432234 = 26567011716117
BaseRepresentation
bin1011111100100000000011…
…0011010001100000101010
31201111121012200020022022222
42333020000303101200222
53210141434444312414
643533404223514042
72523621226105025
oct277100063214052
951447180208288
1013134023432234
114204120908031
121581565a58922
137436c1297083
143359939c41bc
1517b9a584d68e
hexbf200cd182a

13134023432234 has 4 divisors (see below), whose sum is σ = 19701035148354. Its totient is φ = 6567011716116.

The previous prime is 13134023432221. The next prime is 13134023432251. The reversal of 13134023432234 is 43223432043131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12362080200625 + 771943231609 = 3515975^2 + 878603^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13134023432194 and 13134023432203.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283505858057 + ... + 3283505858060.

Almost surely, 213134023432234 is an apocalyptic number.

13134023432234 is a deficient number, since it is larger than the sum of its proper divisors (6567011716120).

13134023432234 is an equidigital number, since it uses as much as digits as its factorization.

13134023432234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6567011716119.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 13134023432234 its reverse (43223432043131), we get a palindrome (56357455475365).

The spelling of 13134023432234 in words is "thirteen trillion, one hundred thirty-four billion, twenty-three million, four hundred thirty-two thousand, two hundred thirty-four".

Divisors: 1 2 6567011716117 13134023432234