Base | Representation |
---|---|
bin | 1011111100100000000011… |
… | …0011010001100000101010 |
3 | 1201111121012200020022022222 |
4 | 2333020000303101200222 |
5 | 3210141434444312414 |
6 | 43533404223514042 |
7 | 2523621226105025 |
oct | 277100063214052 |
9 | 51447180208288 |
10 | 13134023432234 |
11 | 4204120908031 |
12 | 1581565a58922 |
13 | 7436c1297083 |
14 | 3359939c41bc |
15 | 17b9a584d68e |
hex | bf200cd182a |
13134023432234 has 4 divisors (see below), whose sum is σ = 19701035148354. Its totient is φ = 6567011716116.
The previous prime is 13134023432221. The next prime is 13134023432251. The reversal of 13134023432234 is 43223432043131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12362080200625 + 771943231609 = 3515975^2 + 878603^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13134023432194 and 13134023432203.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283505858057 + ... + 3283505858060.
Almost surely, 213134023432234 is an apocalyptic number.
13134023432234 is a deficient number, since it is larger than the sum of its proper divisors (6567011716120).
13134023432234 is an equidigital number, since it uses as much as digits as its factorization.
13134023432234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6567011716119.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 13134023432234 its reverse (43223432043131), we get a palindrome (56357455475365).
The spelling of 13134023432234 in words is "thirteen trillion, one hundred thirty-four billion, twenty-three million, four hundred thirty-two thousand, two hundred thirty-four".
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