13134024012433 has 8 divisors (see below), whose sum is σ = 13826228137920. Its totient is φ = 12441913857360.

The previous prime is 13134024012401. The next prime is 13134024012493. The reversal of 13134024012433 is 33421042043131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13134024012433 - 2⁵ = 13134024012401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13134024012395 and 13134024012404.

It is not an unprimeable number, because it can be changed into a prime (13134024012493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23205613 + ... + 23764858.

It is an arithmetic number, because the mean of its divisors is an integer number (1728278517240).

Almost surely, 2^{13134024012433} is an apocalyptic number.

It is an amenable number.

13134024012433 is a deficient number, since it is larger than the sum of its proper divisors (692204125487).

13134024012433 is a wasteful number, since it uses less digits than its factorization.

13134024012433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46985207.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13134024012433 its reverse (33421042043131), we get a palindrome (46555066055564).

The spelling of 13134024012433 in words is "thirteen trillion, one hundred thirty-four billion, twenty-four million, twelve thousand, four hundred thirty-three".