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1313410245041 is a prime number
BaseRepresentation
bin10011000111001101010…
…110011110000110110001
311122120010211002111002102
4103013031112132012301
5133004331010320131
62443212231430145
7163614346610606
oct23071526360661
94576124074072
101313410245041
1146701792a834
1219266a525355
1396b1448698b
14477d85c46ad
15242713b11cb
hex131cd59e1b1

1313410245041 has 2 divisors, whose sum is σ = 1313410245042. Its totient is φ = 1313410245040.

The previous prime is 1313410245001. The next prime is 1313410245047. The reversal of 1313410245041 is 1405420143131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1223227152016 + 90183093025 = 1105996^2 + 300305^2 .

It is an emirp because it is prime and its reverse (1405420143131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313410245041 - 226 = 1313343136177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313410244995 and 1313410245013.

It is not a weakly prime, because it can be changed into another prime (1313410245047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656705122520 + 656705122521.

It is an arithmetic number, because the mean of its divisors is an integer number (656705122521).

Almost surely, 21313410245041 is an apocalyptic number.

It is an amenable number.

1313410245041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313410245041 is an equidigital number, since it uses as much as digits as its factorization.

1313410245041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 1313410245041 its reverse (1405420143131), we get a palindrome (2718830388172).

The spelling of 1313410245041 in words is "one trillion, three hundred thirteen billion, four hundred ten million, two hundred forty-five thousand, forty-one".