1313414361403 has 4 divisors (see below), whose sum is σ = 1313417818168. Its totient is φ = 1313410904640.

The previous prime is 1313414361383. The next prime is 1313414361439. The reversal of 1313414361403 is 3041634143131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313414361403 - 2¹³ = 1313414353211 is a prime.

It is a super-2 number, since 2×1313414361403² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313414361463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1076493 + ... + 1945678.

It is an arithmetic number, because the mean of its divisors is an integer number (328354454542).

Almost surely, 2^{1313414361403} is an apocalyptic number.

1313414361403 is a deficient number, since it is larger than the sum of its proper divisors (3456765).

1313414361403 is an equidigital number, since it uses as much as digits as its factorization.

1313414361403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3456764.

The product of its (nonzero) digits is 31104, while the sum is 34.

The spelling of 1313414361403 in words is "one trillion, three hundred thirteen billion, four hundred fourteen million, three hundred sixty-one thousand, four hundred three".