Base | Representation |
---|---|
bin | 1011111100100000101101… |
… | …1001110101001111100111 |
3 | 1201111121200001221112211000 |
4 | 2333020023121311033213 |
5 | 3210142321013442411 |
6 | 43533434020244343 |
7 | 2523625516053426 |
oct | 277101331651747 |
9 | 51447601845730 |
10 | 13134201312231 |
11 | 420420226199a |
12 | 15815b55406b3 |
13 | 74371c0a7ccc |
14 | 3359ad4892bd |
15 | 17b9b6288956 |
hex | bf20b6753e7 |
13134201312231 has 16 divisors (see below), whose sum is σ = 19468142353120. Its totient is φ = 8751604357440.
The previous prime is 13134201312173. The next prime is 13134201312257. The reversal of 13134201312231 is 13221310243131.
13134201312231 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 420 + 1 + 3 + 1 + 2 + 231 = 666.
It is not a de Polignac number, because 13134201312231 - 233 = 13125611377639 is a prime.
It is a super-2 number, since 2×131342013122312 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13134201312195 and 13134201312204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134201314231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 125776030 + ... + 125880411.
It is an arithmetic number, because the mean of its divisors is an integer number (1216758897070).
Almost surely, 213134201312231 is an apocalyptic number.
13134201312231 is a deficient number, since it is larger than the sum of its proper divisors (6333941040889).
13134201312231 is a wasteful number, since it uses less digits than its factorization.
13134201312231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 251658383 (or 251658377 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 13134201312231 its reverse (13221310243131), we get a palindrome (26355511555362).
The spelling of 13134201312231 in words is "thirteen trillion, one hundred thirty-four billion, two hundred one million, three hundred twelve thousand, two hundred thirty-one".
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