Base | Representation |
---|---|
bin | 1011111100100000110010… |
… | …1001111010000011010011 |
3 | 1201111121201112110000100022 |
4 | 2333020030221322003103 |
5 | 3210142341402202233 |
6 | 43533440050214055 |
7 | 2523626162351333 |
oct | 277101451720323 |
9 | 51447645400308 |
10 | 13134222303443 |
11 | 42042130999aa |
12 | 158160058432b |
13 | 743723547647 |
14 | 3359b21910c3 |
15 | 17b9b8033398 |
hex | bf20ca7a0d3 |
13134222303443 has 2 divisors, whose sum is σ = 13134222303444. Its totient is φ = 13134222303442.
The previous prime is 13134222303413. The next prime is 13134222303451. The reversal of 13134222303443 is 34430322243131.
13134222303443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13134222303443 - 28 = 13134222303187 is a prime.
It is not a weakly prime, because it can be changed into another prime (13134222303403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567111151721 + 6567111151722.
It is an arithmetic number, because the mean of its divisors is an integer number (6567111151722).
Almost surely, 213134222303443 is an apocalyptic number.
13134222303443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134222303443 is an equidigital number, since it uses as much as digits as its factorization.
13134222303443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 13134222303443 its reverse (34430322243131), we get a palindrome (47564544546574).
The spelling of 13134222303443 in words is "thirteen trillion, one hundred thirty-four billion, two hundred twenty-two million, three hundred three thousand, four hundred forty-three".
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