131342424014433 has 4 divisors (see below), whose sum is σ = 175123232019248. Its totient is φ = 87561616009620.

The previous prime is 131342424014413. The next prime is 131342424014587. The reversal of 131342424014433 is 334410424243131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131342424014433 - 2⁹ = 131342424013921 is a prime.

It is a super-2 number, since 2×131342424014433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131342424014391 and 131342424014400.

It is not an unprimeable number, because it can be changed into a prime (131342424014413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21890404002403 + ... + 21890404002408.

It is an arithmetic number, because the mean of its divisors is an integer number (43780808004812).

Almost surely, 2^{131342424014433} is an apocalyptic number.

It is an amenable number.

131342424014433 is a deficient number, since it is larger than the sum of its proper divisors (43780808004815).

131342424014433 is an equidigital number, since it uses as much as digits as its factorization.

131342424014433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43780808004814.

The product of its (nonzero) digits is 331776, while the sum is 39.

Adding to 131342424014433 its reverse (334410424243131), we get a palindrome (465752848257564).

The spelling of 131342424014433 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred twenty-four million, fourteen thousand, four hundred thirty-three".