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13134253342489 is a prime number
BaseRepresentation
bin1011111100100000111010…
…0000010011111100011001
31201111121210200211221220121
42333020032200103330121
53210142422323424424
643533443115353241
72523630020235226
oct277101640237431
951447720757817
1013134253342489
11420422966a004
12158160aa52821
13743729ac4546
143359b635094d
1517b9bab14ee4
hexbf20e813f19

13134253342489 has 2 divisors, whose sum is σ = 13134253342490. Its totient is φ = 13134253342488.

The previous prime is 13134253342409. The next prime is 13134253342523. The reversal of 13134253342489 is 98424335243131.

13134253342489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8846073835225 + 4288179507264 = 2974235^2 + 2070792^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134253342489 - 213 = 13134253334297 is a prime.

It is a super-2 number, since 2×131342533424892 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13134253342409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567126671244 + 6567126671245.

It is an arithmetic number, because the mean of its divisors is an integer number (6567126671245).

Almost surely, 213134253342489 is an apocalyptic number.

It is an amenable number.

13134253342489 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134253342489 is an equidigital number, since it uses as much as digits as its factorization.

13134253342489 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7464960, while the sum is 52.

The spelling of 13134253342489 in words is "thirteen trillion, one hundred thirty-four billion, two hundred fifty-three million, three hundred forty-two thousand, four hundred eighty-nine".