Base | Representation |
---|---|
bin | 1011111100100001001001… |
… | …1111110010011010100011 |
3 | 1201111121222100212110120122 |
4 | 2333020102133302122203 |
5 | 3210143042000022034 |
6 | 43533453511030455 |
7 | 2523631462416422 |
oct | 277102237623243 |
9 | 51447870773518 |
10 | 13134320314019 |
11 | 4204263451783 |
12 | 158162936b42b |
13 | 74373a942778 |
14 | 3359c11c52b9 |
15 | 17b9c194362e |
hex | bf2127f26a3 |
13134320314019 has 2 divisors, whose sum is σ = 13134320314020. Its totient is φ = 13134320314018.
The previous prime is 13134320314009. The next prime is 13134320314039. The reversal of 13134320314019 is 91041302343131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13134320314019 is a prime.
It is a super-2 number, since 2×131343203140192 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13134320314019.
It is not a weakly prime, because it can be changed into another prime (13134320314009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567160157009 + 6567160157010.
It is an arithmetic number, because the mean of its divisors is an integer number (6567160157010).
Almost surely, 213134320314019 is an apocalyptic number.
13134320314019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134320314019 is an equidigital number, since it uses as much as digits as its factorization.
13134320314019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 13134320314019 in words is "thirteen trillion, one hundred thirty-four billion, three hundred twenty million, three hundred fourteen thousand, nineteen".
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