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131343214213403 = 1038131265190431
BaseRepresentation
bin11101110111010010111001…
…101000000111100100011011
3122020001021210102112020101022
4131313102321220013210123
5114203411400314312103
61143202123432113055
736444143201142413
oct3567227150074433
9566037712466338
10131343214213403
1138939387349575
121289324083578b
1358397c5608caa
14246108cb5d643
15102b812260138
hex7774b9a0791b

131343214213403 has 4 divisors (see below), whose sum is σ = 131344479507648. Its totient is φ = 131341948919160.

The previous prime is 131343214213363. The next prime is 131343214213427. The reversal of 131343214213403 is 304312412343131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131343214213403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131343214203403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 632491403 + ... + 632699028.

It is an arithmetic number, because the mean of its divisors is an integer number (32836119876912).

Almost surely, 2131343214213403 is an apocalyptic number.

131343214213403 is a deficient number, since it is larger than the sum of its proper divisors (1265294245).

131343214213403 is a wasteful number, since it uses less digits than its factorization.

131343214213403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1265294244.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 131343214213403 its reverse (304312412343131), we get a palindrome (435655626556534).

The spelling of 131343214213403 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred fourteen million, two hundred thirteen thousand, four hundred three".

Divisors: 1 103813 1265190431 131343214213403