Base | Representation |
---|---|
bin | 11101110111010010111001… |
… | …101000000111100100011011 |
3 | 122020001021210102112020101022 |
4 | 131313102321220013210123 |
5 | 114203411400314312103 |
6 | 1143202123432113055 |
7 | 36444143201142413 |
oct | 3567227150074433 |
9 | 566037712466338 |
10 | 131343214213403 |
11 | 38939387349575 |
12 | 1289324083578b |
13 | 58397c5608caa |
14 | 246108cb5d643 |
15 | 102b812260138 |
hex | 7774b9a0791b |
131343214213403 has 4 divisors (see below), whose sum is σ = 131344479507648. Its totient is φ = 131341948919160.
The previous prime is 131343214213363. The next prime is 131343214213427. The reversal of 131343214213403 is 304312412343131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131343214213403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131343214203403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 632491403 + ... + 632699028.
It is an arithmetic number, because the mean of its divisors is an integer number (32836119876912).
Almost surely, 2131343214213403 is an apocalyptic number.
131343214213403 is a deficient number, since it is larger than the sum of its proper divisors (1265294245).
131343214213403 is a wasteful number, since it uses less digits than its factorization.
131343214213403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1265294244.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 131343214213403 its reverse (304312412343131), we get a palindrome (435655626556534).
The spelling of 131343214213403 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred fourteen million, two hundred thirteen thousand, four hundred three".
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