Base | Representation |
---|---|
bin | 11101110111010010111001… |
… | …101000000111100101001011 |
3 | 122020001021210102112020110002 |
4 | 131313102321220013211023 |
5 | 114203411400314312301 |
6 | 1143202123432113215 |
7 | 36444143201142512 |
oct | 3567227150074513 |
9 | 566037712466402 |
10 | 131343214213451 |
11 | 38939387349609 |
12 | 1289324083580b |
13 | 58397c5609016 |
14 | 246108cb5d679 |
15 | 102b81226016b |
hex | 7774b9a0794b |
131343214213451 has 2 divisors, whose sum is σ = 131343214213452. Its totient is φ = 131343214213450.
The previous prime is 131343214213441. The next prime is 131343214213513. The reversal of 131343214213451 is 154312412343131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131343214213451 is a prime.
It is not a weakly prime, because it can be changed into another prime (131343214213441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671607106725 + 65671607106726.
It is an arithmetic number, because the mean of its divisors is an integer number (65671607106726).
Almost surely, 2131343214213451 is an apocalyptic number.
131343214213451 is a deficient number, since it is larger than the sum of its proper divisors (1).
131343214213451 is an equidigital number, since it uses as much as digits as its factorization.
131343214213451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 38.
Adding to 131343214213451 its reverse (154312412343131), we get a palindrome (285655626556582).
The spelling of 131343214213451 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred fourteen million, two hundred thirteen thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •