Base | Representation |
---|---|
bin | 11101110111010100000110… |
… | …100010010000101010010011 |
3 | 122020001102010100110202221212 |
4 | 131313110012202100222103 |
5 | 114203422021124222121 |
6 | 1143202455444010335 |
7 | 36444220156454234 |
oct | 3567240642205223 |
9 | 566042110422855 |
10 | 131344504523411 |
11 | 38939989728583 |
12 | 128935409909ab |
13 | 583996ca3053a |
14 | 246117227b08b |
15 | 102b88a68925b |
hex | 777506890a93 |
131344504523411 has 4 divisors (see below), whose sum is σ = 134548029024024. Its totient is φ = 128140980022800.
The previous prime is 131344504523399. The next prime is 131344504523423. The reversal of 131344504523411 is 114325405443131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131344504523399) and next prime (131344504523423).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131344504523411 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41), and also a Moran number because the ratio is a prime number: 3203524500571 = 131344504523411 / (1 + 3 + 1 + 3 + 4 + 4 + 5 + 0 + 4 + 5 + 2 + 3 + 4 + 1 + 1).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131344504523431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1601762250245 + ... + 1601762250326.
It is an arithmetic number, because the mean of its divisors is an integer number (33637007256006).
Almost surely, 2131344504523411 is an apocalyptic number.
131344504523411 is a deficient number, since it is larger than the sum of its proper divisors (3203524500613).
131344504523411 is an equidigital number, since it uses as much as digits as its factorization.
131344504523411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3203524500612.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 131344504523411 its reverse (114325405443131), we get a palindrome (245669909966542).
The spelling of 131344504523411 in words is "one hundred thirty-one trillion, three hundred forty-four billion, five hundred four million, five hundred twenty-three thousand, four hundred eleven".
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