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131344544121113 is a prime number
BaseRepresentation
bin11101110111010100001000…
…111001010100000100011001
3122020001102020002222112210102
4131313110020321110010121
5114203422111243333423
61143202503420425145
736444221150155361
oct3567241071240431
9566042202875712
10131344544121113
11389399aa013954
12128935520a81b5
135839977cb5c2b
1424611776279a1
15102b88ddabc28
hex777508e54119

131344544121113 has 2 divisors, whose sum is σ = 131344544121114. Its totient is φ = 131344544121112.

The previous prime is 131344544121097. The next prime is 131344544121127. The reversal of 131344544121113 is 311121445443131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116481768899584 + 14862775221529 = 10792672^2 + 3855227^2 .

It is a cyclic number.

It is not a de Polignac number, because 131344544121113 - 24 = 131344544121097 is a prime.

It is a super-2 number, since 2×1313445441211132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131344544111113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672272060556 + 65672272060557.

It is an arithmetic number, because the mean of its divisors is an integer number (65672272060557).

Almost surely, 2131344544121113 is an apocalyptic number.

It is an amenable number.

131344544121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131344544121113 is an equidigital number, since it uses as much as digits as its factorization.

131344544121113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69120, while the sum is 38.

Adding to 131344544121113 its reverse (311121445443131), we get a palindrome (442465989564244).

The spelling of 131344544121113 in words is "one hundred thirty-one trillion, three hundred forty-four billion, five hundred forty-four million, one hundred twenty-one thousand, one hundred thirteen".