Base | Representation |
---|---|
bin | 11101110111010100111101… |
… | …011011001000101001001001 |
3 | 122020001111111112021021111121 |
4 | 131313110331123020221021 |
5 | 114203430412400334231 |
6 | 1143203131101355241 |
7 | 36444252041012605 |
oct | 3567247533105111 |
9 | 566044445237447 |
10 | 131345425402441 |
11 | 3893a311520628 |
12 | 12893759268b21 |
13 | 5839a88757483 |
14 | 246121c6b0505 |
15 | 102b8e143c311 |
hex | 77753d6c8a49 |
131345425402441 has 2 divisors, whose sum is σ = 131345425402442. Its totient is φ = 131345425402440.
The previous prime is 131345425402319. The next prime is 131345425402453. The reversal of 131345425402441 is 144204524543131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128469280756041 + 2876144646400 = 11334429^2 + 1695920^2 .
It is a cyclic number.
It is not a de Polignac number, because 131345425402441 - 219 = 131345424878153 is a prime.
It is not a weakly prime, because it can be changed into another prime (131345425403441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672712701220 + 65672712701221.
It is an arithmetic number, because the mean of its divisors is an integer number (65672712701221).
Almost surely, 2131345425402441 is an apocalyptic number.
It is an amenable number.
131345425402441 is a deficient number, since it is larger than the sum of its proper divisors (1).
131345425402441 is an equidigital number, since it uses as much as digits as its factorization.
131345425402441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 921600, while the sum is 43.
Adding to 131345425402441 its reverse (144204524543131), we get a palindrome (275549949945572).
The spelling of 131345425402441 in words is "one hundred thirty-one trillion, three hundred forty-five billion, four hundred twenty-five million, four hundred two thousand, four hundred forty-one".
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