Search a number
-
+
131350034801 is a prime number
BaseRepresentation
bin111101001010100010…
…0100111100101110001
3110120001000021010012202
41322111010213211301
54123001102103201
6140201423032545
712326655605606
oct1722504474561
9416030233182
10131350034801
1150783741277
1221558a3b755
13c5037aa9ab
1465008d26ad
15363b638c6b
hex1e95127971

131350034801 has 2 divisors, whose sum is σ = 131350034802. Its totient is φ = 131350034800.

The previous prime is 131350034723. The next prime is 131350034831. The reversal of 131350034801 is 108430053131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66018163600 + 65331871201 = 256940^2 + 255601^2 .

It is a cyclic number.

It is not a de Polignac number, because 131350034801 - 210 = 131350033777 is a prime.

It is a super-2 number, since 2×1313500348012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131350034831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65675017400 + 65675017401.

It is an arithmetic number, because the mean of its divisors is an integer number (65675017401).

Almost surely, 2131350034801 is an apocalyptic number.

It is an amenable number.

131350034801 is a deficient number, since it is larger than the sum of its proper divisors (1).

131350034801 is an equidigital number, since it uses as much as digits as its factorization.

131350034801 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 131350034801 its reverse (108430053131), we get a palindrome (239780087932).

The spelling of 131350034801 in words is "one hundred thirty-one billion, three hundred fifty million, thirty-four thousand, eight hundred one".