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131350035697 = 314467417691
BaseRepresentation
bin111101001010100010…
…0100111110011110001
3110120001000021011102221
41322111010213303301
54123001102120242
6140201423041041
712326655611326
oct1722504476361
9416030234387
10131350035697
1150783741a11
1221558a40181
13c5037ab21a
1465008d2b4d
15363b639167
hex1e95127cf1

131350035697 has 4 divisors (see below), whose sum is σ = 131350767856. Its totient is φ = 131349303540.

The previous prime is 131350035673. The next prime is 131350035701. The reversal of 131350035697 is 796530053131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 796530053131 = 5315028868927.

It is a cyclic number.

It is not a de Polignac number, because 131350035697 - 215 = 131350002929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131350035637) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105622 + ... + 523312.

It is an arithmetic number, because the mean of its divisors is an integer number (32837691964).

Almost surely, 2131350035697 is an apocalyptic number.

It is an amenable number.

131350035697 is a deficient number, since it is larger than the sum of its proper divisors (732159).

131350035697 is an equidigital number, since it uses as much as digits as its factorization.

131350035697 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 732158.

The product of its (nonzero) digits is 255150, while the sum is 43.

The spelling of 131350035697 in words is "one hundred thirty-one billion, three hundred fifty million, thirty-five thousand, six hundred ninety-seven".

Divisors: 1 314467 417691 131350035697