Base | Representation |
---|---|
bin | 11101110111011001100111… |
… | …001101100000101110011011 |
3 | 122020001222101201012100120212 |
4 | 131313121213031200232123 |
5 | 114204021130342111220 |
6 | 1143205314532041335 |
7 | 36444516614442140 |
oct | 3567314715405633 |
9 | 566058351170525 |
10 | 131350421441435 |
11 | 38941445672679 |
12 | 1289471246324b |
13 | 583a3a382a171 |
14 | 24615740203c7 |
15 | 102bad4d600c5 |
hex | 777667360b9b |
131350421441435 has 16 divisors (see below), whose sum is σ = 189618653510400. Its totient is φ = 85328394078816.
The previous prime is 131350421441429. The next prime is 131350421441483. The reversal of 131350421441435 is 534144124053131.
It is not a de Polignac number, because 131350421441435 - 28 = 131350421441179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131350421441392 and 131350421441401.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 98759714705 + ... + 98759716034.
It is an arithmetic number, because the mean of its divisors is an integer number (11851165844400).
Almost surely, 2131350421441435 is an apocalyptic number.
131350421441435 is a deficient number, since it is larger than the sum of its proper divisors (58268232068965).
131350421441435 is a wasteful number, since it uses less digits than its factorization.
131350421441435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197519430770.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 131350421441435 its reverse (534144124053131), we get a palindrome (665494545494566).
The spelling of 131350421441435 in words is "one hundred thirty-one trillion, three hundred fifty billion, four hundred twenty-one million, four hundred forty-one thousand, four hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •