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13135223600042 = 26567611800021
BaseRepresentation
bin1011111100100100100001…
…0101100011001110101010
31201111201022022120011001112
42333021020111203032222
53210201414220200132
643534123255350322
72523663041262365
oct277111025431652
951451268504045
1013135223600042
114204687318955
12158183b9823a2
13743852b19a3b
14335a691590dc
1517ba25dbdab2
hexbf2485633aa

13135223600042 has 4 divisors (see below), whose sum is σ = 19702835400066. Its totient is φ = 6567611800020.

The previous prime is 13135223599969. The next prime is 13135223600053. The reversal of 13135223600042 is 24000632253131.

13135223600042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8111667913801 + 5023555686241 = 2848099^2 + 2241329^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13135223599981 and 13135223600008.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283805900009 + ... + 3283805900012.

Almost surely, 213135223600042 is an apocalyptic number.

13135223600042 is a deficient number, since it is larger than the sum of its proper divisors (6567611800024).

13135223600042 is an equidigital number, since it uses as much as digits as its factorization.

13135223600042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6567611800023.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 13135223600042 its reverse (24000632253131), we get a palindrome (37135855853173).

The spelling of 13135223600042 in words is "thirteen trillion, one hundred thirty-five billion, two hundred twenty-three million, six hundred thousand, forty-two".

Divisors: 1 2 6567611800021 13135223600042