Base | Representation |
---|---|
bin | 1011111100100100100001… |
… | …0101100011001110101010 |
3 | 1201111201022022120011001112 |
4 | 2333021020111203032222 |
5 | 3210201414220200132 |
6 | 43534123255350322 |
7 | 2523663041262365 |
oct | 277111025431652 |
9 | 51451268504045 |
10 | 13135223600042 |
11 | 4204687318955 |
12 | 158183b9823a2 |
13 | 743852b19a3b |
14 | 335a691590dc |
15 | 17ba25dbdab2 |
hex | bf2485633aa |
13135223600042 has 4 divisors (see below), whose sum is σ = 19702835400066. Its totient is φ = 6567611800020.
The previous prime is 13135223599969. The next prime is 13135223600053. The reversal of 13135223600042 is 24000632253131.
13135223600042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8111667913801 + 5023555686241 = 2848099^2 + 2241329^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13135223599981 and 13135223600008.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283805900009 + ... + 3283805900012.
Almost surely, 213135223600042 is an apocalyptic number.
13135223600042 is a deficient number, since it is larger than the sum of its proper divisors (6567611800024).
13135223600042 is an equidigital number, since it uses as much as digits as its factorization.
13135223600042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6567611800023.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 13135223600042 its reverse (24000632253131), we get a palindrome (37135855853173).
The spelling of 13135223600042 in words is "thirteen trillion, one hundred thirty-five billion, two hundred twenty-three million, six hundred thousand, forty-two".
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