Base | Representation |
---|---|
bin | 1011111100100101001110… |
… | …0110001010011010101011 |
3 | 1201111201210111000110220010 |
4 | 2333021103212022122223 |
5 | 3210202311100113420 |
6 | 43534154124303003 |
7 | 2524000524034440 |
oct | 277112346123253 |
9 | 51451714013803 |
10 | 13135412504235 |
11 | 4204773a1241a |
12 | 15818930a1a63 |
13 | 743882cba778 |
14 | 335a8628d9c7 |
15 | 17ba377854e0 |
hex | bf25398a6ab |
13135412504235 has 32 divisors (see below), whose sum is σ = 24266658995712. Its totient is φ = 5942855255040.
The previous prime is 13135412504173. The next prime is 13135412504261. The reversal of 13135412504235 is 53240521453131.
It is not a de Polignac number, because 13135412504235 - 26 = 13135412504171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13135412504193 and 13135412504202.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 644830881 + ... + 644851250.
It is an arithmetic number, because the mean of its divisors is an integer number (758333093616).
Almost surely, 213135412504235 is an apocalyptic number.
13135412504235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13135412504235 is a deficient number, since it is larger than the sum of its proper divisors (11131246491477).
13135412504235 is a wasteful number, since it uses less digits than its factorization.
13135412504235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1289682243.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 13135412504235 its reverse (53240521453131), we get a palindrome (66375933957366).
The spelling of 13135412504235 in words is "thirteen trillion, one hundred thirty-five billion, four hundred twelve million, five hundred four thousand, two hundred thirty-five".
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