1313553650113 has 2 divisors, whose sum is σ = 1313553650114. Its totient is φ = 1313553650112.

The previous prime is 1313553650081. The next prime is 1313553650159. The reversal of 1313553650113 is 3110563553131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1241468380944 + 72085269169 = 1114212^2 + 268487^2 .

It is an emirp because it is prime and its reverse (3110563553131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313553650113 - 2⁵ = 1313553650081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1313553650813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656776825056 + 656776825057.

It is an arithmetic number, because the mean of its divisors is an integer number (656776825057).

Almost surely, 2^{1313553650113} is an apocalyptic number.

It is an amenable number.

1313553650113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313553650113 is an equidigital number, since it uses as much as digits as its factorization.

1313553650113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60750, while the sum is 37.

The spelling of 1313553650113 in words is "one trillion, three hundred thirteen billion, five hundred fifty-three million, six hundred fifty thousand, one hundred thirteen".