1313554015331 has 8 divisors (see below), whose sum is σ = 1341530213184. Its totient is φ = 1285578994240.

The previous prime is 1313554015313. The next prime is 1313554015339. The reversal of 1313554015331 is 1335104553131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1313554015331 - 2¹⁰ = 1313554014307 is a prime.

It is a super-2 number, since 2×1313554015331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313554015291 and 1313554015300.

It is not an unprimeable number, because it can be changed into a prime (1313554015339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2181581 + ... + 2717793.

It is an arithmetic number, because the mean of its divisors is an integer number (167691276648).

Almost surely, 2^{1313554015331} is an apocalyptic number.

1313554015331 is a deficient number, since it is larger than the sum of its proper divisors (27976197853).

1313554015331 is an equidigital number, since it uses as much as digits as its factorization.

1313554015331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 588381.

The product of its (nonzero) digits is 40500, while the sum is 35.

Adding to 1313554015331 its reverse (1335104553131), we get a palindrome (2648658568462).

The spelling of 1313554015331 in words is "one trillion, three hundred thirteen billion, five hundred fifty-four million, fifteen thousand, three hundred thirty-one".