Base | Representation |
---|---|
bin | 10011000111010101111… |
… | …100111101100100101011 |
3 | 11122120111212122002120111 |
4 | 103013111330331210223 |
5 | 133010124431200011 |
6 | 2443234424435151 |
7 | 163621051323112 |
oct | 23072574754453 |
9 | 4576455562514 |
10 | 1313554553131 |
11 | 467091334617 |
12 | 1926aa918ab7 |
13 | 96b38341b92 |
14 | 4780d82ac79 |
15 | 2427ddb9121 |
hex | 131d5f3d92b |
1313554553131 has 2 divisors, whose sum is σ = 1313554553132. Its totient is φ = 1313554553130.
The previous prime is 1313554553111. The next prime is 1313554553137.
1313554553131 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1313554553131 - 29 = 1313554552619 is a prime.
It is a super-2 number, since 2×13135545531312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1313554553137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656777276565 + 656777276566.
It is an arithmetic number, because the mean of its divisors is an integer number (656777276566).
Almost surely, 21313554553131 is an apocalyptic number.
1313554553131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313554553131 is an equidigital number, since it uses as much as digits as its factorization.
1313554553131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 202500, while the sum is 40.
The spelling of 1313554553131 in words is "one trillion, three hundred thirteen billion, five hundred fifty-four million, five hundred fifty-three thousand, one hundred thirty-one".
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