13136511563131 has 16 divisors (see below), whose sum is σ = 14411714335200. Its totient is φ = 11874821011200.

The previous prime is 13136511563107. The next prime is 13136511563137.

13136511563131 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 13136511563131 - 2²¹ = 13136509465979 is a prime.

It is a super-2 number, since 2×13136511563131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13136511563137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15697365 + ... + 16513033.

It is an arithmetic number, because the mean of its divisors is an integer number (900732145950).

Almost surely, 2^{13136511563131} is an apocalyptic number.

13136511563131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13136511563131 is a deficient number, since it is larger than the sum of its proper divisors (1275202772069).

13136511563131 is a wasteful number, since it uses less digits than its factorization.

13136511563131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 823950.

The product of its digits is 72900, while the sum is 40.

It can be divided in two parts, 1313651 and 1563131, that added together give a palindrome (2876782).

The spelling of 13136511563131 in words is "thirteen trillion, one hundred thirty-six billion, five hundred eleven million, five hundred sixty-three thousand, one hundred thirty-one".