Base | Representation |
---|---|
bin | 111101001011000000… |
… | …1011111101011011001 |
3 | 110120002010021212222201 |
4 | 1322112001133223121 |
5 | 4123014143240202 |
6 | 140203153050201 |
7 | 12330241342516 |
oct | 1722601375331 |
9 | 416063255881 |
10 | 131365993177 |
11 | 50791751011 |
12 | 21562256961 |
13 | c506ba7613 |
14 | 6502a8830d |
15 | 363cc3c387 |
hex | 1e9605fad9 |
131365993177 has 2 divisors, whose sum is σ = 131365993178. Its totient is φ = 131365993176.
The previous prime is 131365993159. The next prime is 131365993207. The reversal of 131365993177 is 771399563131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 87270613056 + 44095380121 = 295416^2 + 209989^2 .
It is a cyclic number.
It is not a de Polignac number, because 131365993177 - 211 = 131365991129 is a prime.
It is a super-2 number, since 2×1313659931772 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131365993127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65682996588 + 65682996589.
It is an arithmetic number, because the mean of its divisors is an integer number (65682996589).
Almost surely, 2131365993177 is an apocalyptic number.
It is an amenable number.
131365993177 is a deficient number, since it is larger than the sum of its proper divisors (1).
131365993177 is an equidigital number, since it uses as much as digits as its factorization.
131365993177 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3214890, while the sum is 55.
The spelling of 131365993177 in words is "one hundred thirty-one billion, three hundred sixty-five million, nine hundred ninety-three thousand, one hundred seventy-seven".
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