Base | Representation |
---|---|
bin | 11000011110000100… |
… | …10001010110011001 |
3 | 1020220112212122102010 |
4 | 30033002101112121 |
5 | 203401102433411 |
6 | 10011330500133 |
7 | 643356656562 |
oct | 141702212631 |
9 | 36815778363 |
10 | 13137155481 |
11 | 563164439a |
12 | 2667734649 |
13 | 13149243a8 |
14 | 8c8a6d169 |
15 | 51d4e57a6 |
hex | 30f091599 |
13137155481 has 4 divisors (see below), whose sum is σ = 17516207312. Its totient is φ = 8758103652.
The previous prime is 13137155443. The next prime is 13137155491. The reversal of 13137155481 is 18455173131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13137155481 - 29 = 13137154969 is a prime.
It is a super-2 number, since 2×131371554812 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13137155401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2189525911 + ... + 2189525916.
It is an arithmetic number, because the mean of its divisors is an integer number (4379051828).
Almost surely, 213137155481 is an apocalyptic number.
It is an amenable number.
13137155481 is a deficient number, since it is larger than the sum of its proper divisors (4379051831).
13137155481 is an equidigital number, since it uses as much as digits as its factorization.
13137155481 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4379051830.
The product of its digits is 50400, while the sum is 39.
The spelling of 13137155481 in words is "thirteen billion, one hundred thirty-seven million, one hundred fifty-five thousand, four hundred eighty-one".
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