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131374830401 is a prime number
BaseRepresentation
bin111101001011010001…
…1001101001101000001
3110120002201220212101022
41322112203031031001
54123023424033101
6140204110315225
712330406430153
oct1722643151501
9416081825338
10131374830401
1150796737601
12215651b8b15
13c50897cb49
146503d08ad3
15363d8d5a1b
hex1e968cd341

131374830401 has 2 divisors, whose sum is σ = 131374830402. Its totient is φ = 131374830400.

The previous prime is 131374830347. The next prime is 131374830407. The reversal of 131374830401 is 104038473131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123520617025 + 7854213376 = 351455^2 + 88624^2 .

It is an emirp because it is prime and its reverse (104038473131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131374830401 - 26 = 131374830337 is a prime.

It is not a weakly prime, because it can be changed into another prime (131374830407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65687415200 + 65687415201.

It is an arithmetic number, because the mean of its divisors is an integer number (65687415201).

Almost surely, 2131374830401 is an apocalyptic number.

It is an amenable number.

131374830401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131374830401 is an equidigital number, since it uses as much as digits as its factorization.

131374830401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 35.

The spelling of 131374830401 in words is "one hundred thirty-one billion, three hundred seventy-four million, eight hundred thirty thousand, four hundred one".