Base | Representation |
---|---|
bin | 1011111100101111001010… |
… | …1001110110011111111011 |
3 | 1201111222200110100120112112 |
4 | 2333023302221312133323 |
5 | 3210223242222023241 |
6 | 43535315012402535 |
7 | 2524123616220203 |
oct | 277136251663773 |
9 | 51458613316475 |
10 | 13138081048571 |
11 | 4205913274266 |
12 | 15822b891644b |
13 | 743bb9b0c79b |
14 | 335c5a855403 |
15 | 17bb41ba51eb |
hex | bf2f2a767fb |
13138081048571 has 8 divisors (see below), whose sum is σ = 13493253234720. Its totient is φ = 12782913542208.
The previous prime is 13138081048549. The next prime is 13138081048577. The reversal of 13138081048571 is 17584018083131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13138081048571 is a prime.
It is a super-2 number, since 2×131380810485712 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13138081048577) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4947335 + ... + 7124063.
It is an arithmetic number, because the mean of its divisors is an integer number (1686656654340).
Almost surely, 213138081048571 is an apocalyptic number.
13138081048571 is a deficient number, since it is larger than the sum of its proper divisors (355172186149).
13138081048571 is a wasteful number, since it uses less digits than its factorization.
13138081048571 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2339893.
The product of its (nonzero) digits is 645120, while the sum is 50.
The spelling of 13138081048571 in words is "thirteen trillion, one hundred thirty-eight billion, eighty-one million, forty-eight thousand, five hundred seventy-one".
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