13140044011 has 2 divisors, whose sum is σ = 13140044012. Its totient is φ = 13140044010.

The previous prime is 13140043991. The next prime is 13140044051. The reversal of 13140044011 is 11044004131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13140044011 - 2¹⁷ = 13139912939 is a prime.

It is a super-2 number, since 2×13140044011² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13140044011.

It is not a weakly prime, because it can be changed into another prime (13140044051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570022005 + 6570022006.

It is an arithmetic number, because the mean of its divisors is an integer number (6570022006).

Almost surely, 2^13140044011 is an apocalyptic number.

13140044011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140044011 is an equidigital number, since it uses as much as digits as its factorization.

13140044011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13140044011 its reverse (11044004131), we get a palindrome (24184048142).

The spelling of 13140044011 in words is "thirteen billion, one hundred forty million, forty-four thousand, eleven".