13140232014121 has 4 divisors (see below), whose sum is σ = 13143924131200. Its totient is φ = 13136539897044.

The previous prime is 13140232014097. The next prime is 13140232014187. The reversal of 13140232014121 is 12141023204131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13140232014121 - 2¹¹ = 13140232012073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13140232014191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1846053201 + ... + 1846060318.

It is an arithmetic number, because the mean of its divisors is an integer number (3285981032800).

Almost surely, 2^{13140232014121} is an apocalyptic number.

It is an amenable number.

13140232014121 is a deficient number, since it is larger than the sum of its proper divisors (3692117079).

13140232014121 is an equidigital number, since it uses as much as digits as its factorization.

13140232014121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3692117078.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13140232014121 its reverse (12141023204131), we get a palindrome (25281255218252).

The spelling of 13140232014121 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-two million, fourteen thousand, one hundred twenty-one".