Base | Representation |
---|---|
bin | 11101111000001001111101… |
… | …011000100010111100010011 |
3 | 122020020221101112000211000111 |
4 | 131320021331120202330103 |
5 | 114210343434224243103 |
6 | 1143245222021502151 |
7 | 36451335210653545 |
oct | 3570117530427423 |
9 | 566227345024014 |
10 | 131402333040403 |
11 | 38961464393287 |
12 | 128a279b571957 |
13 | 5842257632029 |
14 | 2463c9a597695 |
15 | 102d12245486d |
hex | 77827d622f13 |
131402333040403 has 4 divisors (see below), whose sum is σ = 132985493679528. Its totient is φ = 129819172401280.
The previous prime is 131402333040337. The next prime is 131402333040427. The reversal of 131402333040403 is 304040333204131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131402333040403 - 225 = 131402299485971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131402339040403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 791580319438 + ... + 791580319603.
It is an arithmetic number, because the mean of its divisors is an integer number (33246373419882).
Almost surely, 2131402333040403 is an apocalyptic number.
131402333040403 is a deficient number, since it is larger than the sum of its proper divisors (1583160639125).
131402333040403 is an equidigital number, since it uses as much as digits as its factorization.
131402333040403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1583160639124.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 131402333040403 its reverse (304040333204131), we get a palindrome (435442666244534).
The spelling of 131402333040403 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred thirty-three million, forty thousand, four hundred three".
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