Base | Representation |
---|---|
bin | 1011111100110111001011… |
… | …1111010000011010101001 |
3 | 1201112012020111210010101111 |
4 | 2333031302333100122221 |
5 | 3210242144420042101 |
6 | 43540312404550321 |
7 | 2524231152221461 |
oct | 277156277203251 |
9 | 51465214703344 |
10 | 13140234143401 |
11 | 4206818677282 |
12 | 15827b99b23a1 |
13 | 744170bca5b1 |
14 | 335dc27a2ba1 |
15 | 17bc1ac09251 |
hex | bf372fd06a9 |
13140234143401 has 8 divisors (see below), whose sum is σ = 13363014614400. Its totient is φ = 12917455827120.
The previous prime is 13140234143371. The next prime is 13140234143419. The reversal of 13140234143401 is 10434143204131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13140234143401 - 25 = 13140234143369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13140234143431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16060720 + ... + 16859038.
It is an arithmetic number, because the mean of its divisors is an integer number (1670376826800).
Almost surely, 213140234143401 is an apocalyptic number.
It is an amenable number.
13140234143401 is a deficient number, since it is larger than the sum of its proper divisors (222780470999).
13140234143401 is an equidigital number, since it uses as much as digits as its factorization.
13140234143401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1077359.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13140234143401 its reverse (10434143204131), we get a palindrome (23574377347532).
The spelling of 13140234143401 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-four million, one hundred forty-three thousand, four hundred one".
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