Base | Representation |
---|---|
bin | 1011111100110111001101… |
… | …0111100101010000010101 |
3 | 1201112012020221210002201201 |
4 | 2333031303113211100111 |
5 | 3210242203033121323 |
6 | 43540313153352501 |
7 | 2524231260350662 |
oct | 277156327452025 |
9 | 51465227702651 |
10 | 13140240520213 |
11 | 4206821232274 |
12 | 15827bbb68731 |
13 | 744172320c61 |
14 | 335dc3582a69 |
15 | 17bc1b5688ad |
hex | bf3735e5415 |
13140240520213 has 32 divisors (see below), whose sum is σ = 14170156640640. Its totient is φ = 12148183111680.
The previous prime is 13140240520171. The next prime is 13140240520217. The reversal of 13140240520213 is 31202504204131.
It is a cyclic number.
It is not a de Polignac number, because 13140240520213 - 233 = 13131650585621 is a prime.
It is a super-2 number, since 2×131402405202132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140240520217) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 58319533 + ... + 58544413.
It is an arithmetic number, because the mean of its divisors is an integer number (442817395020).
Almost surely, 213140240520213 is an apocalyptic number.
It is an amenable number.
13140240520213 is a deficient number, since it is larger than the sum of its proper divisors (1029916120427).
13140240520213 is a wasteful number, since it uses less digits than its factorization.
13140240520213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225397.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 13140240520213 its reverse (31202504204131), we get a palindrome (44342744724344).
The spelling of 13140240520213 in words is "thirteen trillion, one hundred forty billion, two hundred forty million, five hundred twenty thousand, two hundred thirteen".
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