Base | Representation |
---|---|
bin | 10011000111110001111… |
… | …100100010011101100011 |
3 | 11122121201121100211121222 |
4 | 103013301330202131203 |
5 | 133012110144013011 |
6 | 2443353203005255 |
7 | 163635513306032 |
oct | 23076174423543 |
9 | 4577647324558 |
10 | 1314024204131 |
11 | 467302452341 |
12 | 19280006982b |
13 | 96bb172c192 |
14 | 47855d62719 |
15 | 242aa239ddb |
hex | 131f1f22763 |
1314024204131 has 2 divisors, whose sum is σ = 1314024204132. Its totient is φ = 1314024204130.
The previous prime is 1314024204127. The next prime is 1314024204187.
1314024204131 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1314024204131 - 22 = 1314024204127 is a prime.
It is a super-2 number, since 2×13140242041312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1314024204131.
It is not a weakly prime, because it can be changed into another prime (1314024204631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657012102065 + 657012102066.
It is an arithmetic number, because the mean of its divisors is an integer number (657012102066).
Almost surely, 21314024204131 is an apocalyptic number.
1314024204131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314024204131 is an equidigital number, since it uses as much as digits as its factorization.
1314024204131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
The spelling of 1314024204131 in words is "one trillion, three hundred fourteen billion, twenty-four million, two hundred four thousand, one hundred thirty-one".
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