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131402433521521 is a prime number
BaseRepresentation
bin11101111000001010000011…
…010111110110011101110001
3122020020221122112002210012101
4131320022003113312131301
5114210344140440142041
61143245240011300401
736451340541021451
oct3570120327663561
9566227575083171
10131402433521521
1138961506083228
12128a280914a701
1358422723b3806
142463ca9a71d61
15102d12b1a1b31
hex7782835f6771

131402433521521 has 2 divisors, whose sum is σ = 131402433521522. Its totient is φ = 131402433521520.

The previous prime is 131402433521461. The next prime is 131402433521551. The reversal of 131402433521521 is 125125334204131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68869749488400 + 62532684033121 = 8298780^2 + 7907761^2 .

It is a cyclic number.

It is not a de Polignac number, because 131402433521521 - 27 = 131402433521393 is a prime.

It is not a weakly prime, because it can be changed into another prime (131402433521551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701216760760 + 65701216760761.

It is an arithmetic number, because the mean of its divisors is an integer number (65701216760761).

Almost surely, 2131402433521521 is an apocalyptic number.

It is an amenable number.

131402433521521 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402433521521 is an equidigital number, since it uses as much as digits as its factorization.

131402433521521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 131402433521521 its reverse (125125334204131), we get a palindrome (256527767725652).

The spelling of 131402433521521 in words is "one hundred thirty-one trillion, four hundred two billion, four hundred thirty-three million, five hundred twenty-one thousand, five hundred twenty-one".