Base | Representation |
---|---|
bin | 1011111100110111010000… |
… | …0011110101100011111110 |
3 | 1201112012021202121111111011 |
4 | 2333031310003311203332 |
5 | 3210242214020340332 |
6 | 43540314250145434 |
7 | 2524231461066343 |
oct | 277156403654376 |
9 | 51465252544434 |
10 | 13140252121342 |
11 | 4206827836385 |
12 | 1582803a2227a |
13 | 744174853528 |
14 | 335dc4d227ca |
15 | 17bc1c5aae47 |
hex | bf3740f58fe |
13140252121342 has 16 divisors (see below), whose sum is σ = 19901909675232. Its totient is φ = 6506283310560.
The previous prime is 13140252121303. The next prime is 13140252121369. The reversal of 13140252121342 is 24312125204131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35701492 + ... + 36067672.
It is an arithmetic number, because the mean of its divisors is an integer number (1243869354702).
Almost surely, 213140252121342 is an apocalyptic number.
13140252121342 is a deficient number, since it is larger than the sum of its proper divisors (6761657553890).
13140252121342 is a wasteful number, since it uses less digits than its factorization.
13140252121342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 540483.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 13140252121342 its reverse (24312125204131), we get a palindrome (37452377325473).
The spelling of 13140252121342 in words is "thirteen trillion, one hundred forty billion, two hundred fifty-two million, one hundred twenty-one thousand, three hundred forty-two".
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