Base | Representation |
---|---|
bin | 11101111000001010110011… |
… | …000001101011001011010011 |
3 | 122020021000201020111020100211 |
4 | 131320022303001223023103 |
5 | 114210402310122430413 |
6 | 1143245451211224551 |
7 | 36451366416423643 |
oct | 3570126301531323 |
9 | 566230636436324 |
10 | 131403233014483 |
11 | 389618863a8111 |
12 | 128a29b0a48157 |
13 | 584236bc19981 |
14 | 2463d43d08523 |
15 | 102d17647883d |
hex | 7782b306b2d3 |
131403233014483 has 2 divisors, whose sum is σ = 131403233014484. Its totient is φ = 131403233014482.
The previous prime is 131403233014463. The next prime is 131403233014511. The reversal of 131403233014483 is 384410332304131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131403233014483 is a prime.
It is not a weakly prime, because it can be changed into another prime (131403233014463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701616507241 + 65701616507242.
It is an arithmetic number, because the mean of its divisors is an integer number (65701616507242).
Almost surely, 2131403233014483 is an apocalyptic number.
131403233014483 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403233014483 is an equidigital number, since it uses as much as digits as its factorization.
131403233014483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 40.
The spelling of 131403233014483 in words is "one hundred thirty-one trillion, four hundred three billion, two hundred thirty-three million, fourteen thousand, four hundred eighty-three".
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