131403234121132 has 12 divisors (see below), whose sum is σ = 230097695337720. Its totient is φ = 65661035453216.

The previous prime is 131403234121109. The next prime is 131403234121139. The reversal of 131403234121132 is 231121432304131.

It is a super-2 number, since 2×131403234121132² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131403234121094 and 131403234121103.

It is not an unprimeable number, because it can be changed into a prime (131403234121139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10145394553 + ... + 10145407504.

It is an arithmetic number, because the mean of its divisors is an integer number (19174807944810).

Almost surely, 2^{131403234121132} is an apocalyptic number.

It is an amenable number.

131403234121132 is a deficient number, since it is larger than the sum of its proper divisors (98694461216588).

131403234121132 is a wasteful number, since it uses less digits than its factorization.

131403234121132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20290803680 (or 20290803678 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131403234121132 its reverse (231121432304131), we get a palindrome (362524666425263).

The spelling of 131403234121132 in words is "one hundred thirty-one trillion, four hundred three billion, two hundred thirty-four million, one hundred twenty-one thousand, one hundred thirty-two".