Search a number
-
+
131403310413433 is a prime number
BaseRepresentation
bin11101111000001010110111…
…101000111011011001111001
3122020021000220122010111202121
4131320022313220323121321
5114210402434431212213
61143245503014201241
736451401346334602
oct3570126750733171
9566230818114677
10131403310413433
1138961916062093
12128a2a12953221
135842381c79176
142463d502d4da9
15102d17d16688d
hex7782b7a3b679

131403310413433 has 2 divisors, whose sum is σ = 131403310413434. Its totient is φ = 131403310413432.

The previous prime is 131403310413379. The next prime is 131403310413439. The reversal of 131403310413433 is 334314013304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127125805400064 + 4277505013369 = 11275008^2 + 2068213^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131403310413433 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403310413439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655206716 + 65701655206717.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655206717).

Almost surely, 2131403310413433 is an apocalyptic number.

It is an amenable number.

131403310413433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403310413433 is an equidigital number, since it uses as much as digits as its factorization.

131403310413433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 34.

Adding to 131403310413433 its reverse (334314013304131), we get a palindrome (465717323717564).

The spelling of 131403310413433 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred ten million, four hundred thirteen thousand, four hundred thirty-three".