131403311214137 has 2 divisors, whose sum is σ = 131403311214138. Its totient is φ = 131403311214136.

The previous prime is 131403311214127. The next prime is 131403311214157. The reversal of 131403311214137 is 731412113304131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120239032206736 + 11164279007401 = 10965356^2 + 3341299^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403311214137 - 2⁶ = 131403311214073 is a prime.

It is a super-2 number, since 2×131403311214137² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131403311214097 and 131403311214106.

It is not a weakly prime, because it can be changed into another prime (131403311214127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655607068 + 65701655607069.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655607069).

Almost surely, 2^{131403311214137} is an apocalyptic number.

It is an amenable number.

131403311214137 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403311214137 is an equidigital number, since it uses as much as digits as its factorization.

131403311214137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 35.

Adding to 131403311214137 its reverse (731412113304131), we get a palindrome (862815424518268).

The spelling of 131403311214137 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred fourteen thousand, one hundred thirty-seven".