Search a number
-
+
131403311241017 is a prime number
BaseRepresentation
bin11101111000001010110111…
…101100000101011100111001
3122020021000220200200112222212
4131320022313230011130321
5114210402440134203032
61143245503044024505
736451401356352434
oct3570126754053471
9566230820615885
10131403311241017
1138961916577942
12128a2a13092135
1358423821a8a6a
142463d5046c81b
15102d17d27bbb2
hex7782b7b05739

131403311241017 has 2 divisors, whose sum is σ = 131403311241018. Its totient is φ = 131403311241016.

The previous prime is 131403311240963. The next prime is 131403311241029. The reversal of 131403311241017 is 710142113304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131316496154281 + 86815086736 = 11459341^2 + 294644^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403311241017 - 224 = 131403294463801 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403311241077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655620508 + 65701655620509.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655620509).

Almost surely, 2131403311241017 is an apocalyptic number.

It is an amenable number.

131403311241017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403311241017 is an equidigital number, since it uses as much as digits as its factorization.

131403311241017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 131403311241017 its reverse (710142113304131), we get a palindrome (841545424545148).

The spelling of 131403311241017 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred forty-one thousand, seventeen".