Base | Representation |
---|---|
bin | 11101111000001010110111… |
… | …101111011111000100110001 |
3 | 122020021000220202100211202002 |
4 | 131320022313233133010301 |
5 | 114210402440401214101 |
6 | 1143245503115103345 |
7 | 36451401400054301 |
oct | 3570126757370461 |
9 | 566230822324662 |
10 | 131403312132401 |
11 | 38961917026621 |
12 | 128a2a13441b55 |
13 | 584238242b6ca |
14 | 2463d50621601 |
15 | 102d17d3a5d6b |
hex | 7782b7bdf131 |
131403312132401 has 2 divisors, whose sum is σ = 131403312132402. Its totient is φ = 131403312132400.
The previous prime is 131403312132361. The next prime is 131403312132419. The reversal of 131403312132401 is 104231213304131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102560665946176 + 28842646186225 = 10127224^2 + 5370535^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131403312132401 is a prime.
It is not a weakly prime, because it can be changed into another prime (131403312162401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701656066200 + 65701656066201.
It is an arithmetic number, because the mean of its divisors is an integer number (65701656066201).
Almost surely, 2131403312132401 is an apocalyptic number.
It is an amenable number.
131403312132401 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403312132401 is an equidigital number, since it uses as much as digits as its factorization.
131403312132401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 131403312132401 its reverse (104231213304131), we get a palindrome (235634525436532).
The spelling of 131403312132401 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred twelve million, one hundred thirty-two thousand, four hundred one".
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