131403365012113 has 2 divisors, whose sum is σ = 131403365012114. Its totient is φ = 131403365012112.

The previous prime is 131403365012099. The next prime is 131403365012131. The reversal of 131403365012113 is 311210563304131.

Together with next prime (131403365012131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115096249237264 + 16307115774849 = 10728292^2 + 4038207^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403365012113 - 2⁹ = 131403365011601 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403365015113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701682506056 + 65701682506057.

It is an arithmetic number, because the mean of its divisors is an integer number (65701682506057).

Almost surely, 2^{131403365012113} is an apocalyptic number.

It is an amenable number.

131403365012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403365012113 is an equidigital number, since it uses as much as digits as its factorization.

131403365012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 34.

The spelling of 131403365012113 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred sixty-five million, twelve thousand, one hundred thirteen".