Base | Representation |
---|---|
bin | 11101111000001010111110… |
… | …110001001101001100001011 |
3 | 122020021001012222012100112122 |
4 | 131320022332301031030023 |
5 | 114210403211041231242 |
6 | 1143245522530001455 |
7 | 36451404331114364 |
oct | 3570127661151413 |
9 | 566231188170478 |
10 | 131403430023947 |
11 | 38961977628254 |
12 | 128a2a46a1628b |
13 | 58423a0997a13 |
14 | 2463d6214cb6b |
15 | 102d1888e1ad2 |
hex | 7782bec4d30b |
131403430023947 has 2 divisors, whose sum is σ = 131403430023948. Its totient is φ = 131403430023946.
The previous prime is 131403430023871. The next prime is 131403430023967. The reversal of 131403430023947 is 749320034304131.
It is a strong prime.
It is an emirp because it is prime and its reverse (749320034304131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131403430023947 - 234 = 131386250154763 is a prime.
It is a super-2 number, since 2×1314034300239472 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131403430023898 and 131403430023907.
It is not a weakly prime, because it can be changed into another prime (131403430023967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701715011973 + 65701715011974.
It is an arithmetic number, because the mean of its divisors is an integer number (65701715011974).
Almost surely, 2131403430023947 is an apocalyptic number.
131403430023947 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403430023947 is an equidigital number, since it uses as much as digits as its factorization.
131403430023947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 44.
The spelling of 131403430023947 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty million, twenty-three thousand, nine hundred forty-seven".
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