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131403430023947 is a prime number
BaseRepresentation
bin11101111000001010111110…
…110001001101001100001011
3122020021001012222012100112122
4131320022332301031030023
5114210403211041231242
61143245522530001455
736451404331114364
oct3570127661151413
9566231188170478
10131403430023947
1138961977628254
12128a2a46a1628b
1358423a0997a13
142463d6214cb6b
15102d1888e1ad2
hex7782bec4d30b

131403430023947 has 2 divisors, whose sum is σ = 131403430023948. Its totient is φ = 131403430023946.

The previous prime is 131403430023871. The next prime is 131403430023967. The reversal of 131403430023947 is 749320034304131.

It is a strong prime.

It is an emirp because it is prime and its reverse (749320034304131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131403430023947 - 234 = 131386250154763 is a prime.

It is a super-2 number, since 2×1314034300239472 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131403430023898 and 131403430023907.

It is not a weakly prime, because it can be changed into another prime (131403430023967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701715011973 + 65701715011974.

It is an arithmetic number, because the mean of its divisors is an integer number (65701715011974).

Almost surely, 2131403430023947 is an apocalyptic number.

131403430023947 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403430023947 is an equidigital number, since it uses as much as digits as its factorization.

131403430023947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 653184, while the sum is 44.

The spelling of 131403430023947 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty million, twenty-three thousand, nine hundred forty-seven".