131403432112241 has 4 divisors (see below), whose sum is σ = 131404248175092. Its totient is φ = 131402616049392.

The previous prime is 131403432112229. The next prime is 131403432112247. The reversal of 131403432112241 is 142211234304131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 102707279491600 + 28696152620641 = 10134460^2 + 5356879^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131403432112241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131403432112198 and 131403432112207.

It is not an unprimeable number, because it can be changed into a prime (131403432112247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 407789846 + ... + 408111951.

It is an arithmetic number, because the mean of its divisors is an integer number (32851062043773).

Almost surely, 2^{131403432112241} is an apocalyptic number.

It is an amenable number.

131403432112241 is a deficient number, since it is larger than the sum of its proper divisors (816062851).

131403432112241 is an equidigital number, since it uses as much as digits as its factorization.

131403432112241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 816062850.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 131403432112241 its reverse (142211234304131), we get a palindrome (273614666416372).

The spelling of 131403432112241 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-two million, one hundred twelve thousand, two hundred forty-one".