131403432120555 has 16 divisors (see below), whose sum is σ = 240280561592064. Its totient is φ = 60070140397920.

The previous prime is 131403432120481. The next prime is 131403432120557. The reversal of 131403432120555 is 555021234304131.

It is not a de Polignac number, because 131403432120555 - 2¹⁷ = 131403431989483 is a prime.

It is a super-2 number, since 2×131403432120555² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131403432120557) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 625730629041 + ... + 625730629250.

It is an arithmetic number, because the mean of its divisors is an integer number (15017535099504).

Almost surely, 2^{131403432120555} is an apocalyptic number.

131403432120555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131403432120555 is a deficient number, since it is larger than the sum of its proper divisors (108877129471509).

131403432120555 is a wasteful number, since it uses less digits than its factorization.

131403432120555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1251461258306.

The product of its (nonzero) digits is 216000, while the sum is 39.

Adding to 131403432120555 its reverse (555021234304131), we get a palindrome (686424666424686).

The spelling of 131403432120555 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-two million, one hundred twenty thousand, five hundred fifty-five".