13140343231033 has 4 divisors (see below), whose sum is σ = 13141707620608. Its totient is φ = 13138978841460.

The previous prime is 13140343231007. The next prime is 13140343231049. The reversal of 13140343231033 is 33013234304131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13140343231033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140343230986 and 13140343231004.

It is not an unprimeable number, because it can be changed into a prime (13140343231003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 682180341 + ... + 682199602.

It is an arithmetic number, because the mean of its divisors is an integer number (3285426905152).

Almost surely, 2^{13140343231033} is an apocalyptic number.

It is an amenable number.

13140343231033 is a deficient number, since it is larger than the sum of its proper divisors (1364389575).

13140343231033 is an equidigital number, since it uses as much as digits as its factorization.

13140343231033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1364389574.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13140343231033 its reverse (33013234304131), we get a palindrome (46153577535164).

The spelling of 13140343231033 in words is "thirteen trillion, one hundred forty billion, three hundred forty-three million, two hundred thirty-one thousand, thirty-three".