Base | Representation |
---|---|
bin | 10011000111110010100… |
… | …110010000101110111001 |
3 | 11122121202100221111221222 |
4 | 103013302212100232321 |
5 | 133012120444012221 |
6 | 2443354233241425 |
7 | 163636005261422 |
oct | 23076246205671 |
9 | 4577670844858 |
10 | 1314035141561 |
11 | 46730864283a |
12 | 192803863275 |
13 | 96bb3a8b62c |
14 | 478575ac649 |
15 | 242ab19a9ab |
hex | 131f2990bb9 |
1314035141561 has 4 divisors (see below), whose sum is σ = 1314038321232. Its totient is φ = 1314031961892.
The previous prime is 1314035141521. The next prime is 1314035141609. The reversal of 1314035141561 is 1651415304131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1314035141561 - 214 = 1314035125177 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1314035141521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857495 + ... + 1833948.
It is an arithmetic number, because the mean of its divisors is an integer number (328509580308).
Almost surely, 21314035141561 is an apocalyptic number.
It is an amenable number.
1314035141561 is a deficient number, since it is larger than the sum of its proper divisors (3179671).
1314035141561 is an equidigital number, since it uses as much as digits as its factorization.
1314035141561 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3179670.
The product of its (nonzero) digits is 21600, while the sum is 35.
The spelling of 1314035141561 in words is "one trillion, three hundred fourteen billion, thirty-five million, one hundred forty-one thousand, five hundred sixty-one".
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