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131403520314403 is a prime number
BaseRepresentation
bin11101111000001011000100…
…001001101000110000100011
3122020021001110021002120202121
4131320023010021220300203
5114210403402200030103
61143245535513125111
736451406505430021
oct3570130411506043
9566231407076677
10131403520314403
1138961a13597867
12128a2a710b9797
1358423b65bbc1c
142463d70133711
15102d1917c96bd
hex7782c4268c23

131403520314403 has 2 divisors, whose sum is σ = 131403520314404. Its totient is φ = 131403520314402.

The previous prime is 131403520314349. The next prime is 131403520314421. The reversal of 131403520314403 is 304413025304131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131403520314403 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403520317403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701760157201 + 65701760157202.

It is an arithmetic number, because the mean of its divisors is an integer number (65701760157202).

Almost surely, 2131403520314403 is an apocalyptic number.

131403520314403 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403520314403 is an equidigital number, since it uses as much as digits as its factorization.

131403520314403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 131403520314403 its reverse (304413025304131), we get a palindrome (435816545618534).

The spelling of 131403520314403 in words is "one hundred thirty-one trillion, four hundred three billion, five hundred twenty million, three hundred fourteen thousand, four hundred three".