131403520314441 has 16 divisors (see below), whose sum is σ = 194694153419520. Its totient is φ = 87592324713840.

The previous prime is 131403520314439. The next prime is 131403520314541. The reversal of 131403520314441 is 144413025304131.

131403520314441 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 0 + 3 + 5 + 203 + 1 + 4 + 441 = 666.

It is not a de Polignac number, because 131403520314441 - 2¹ = 131403520314439 is a prime.

It is a super-4 number, since 4×131403520314441⁴ (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131403520314396 and 131403520314405.

It is not an unprimeable number, because it can be changed into a prime (131403520314421) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 278153025 + ... + 278625038.

It is an arithmetic number, because the mean of its divisors is an integer number (12168384588720).

Almost surely, 2^{131403520314441} is an apocalyptic number.

It is an amenable number.

131403520314441 is a deficient number, since it is larger than the sum of its proper divisors (63290633105079).

131403520314441 is an equidigital number, since it uses as much as digits as its factorization.

131403520314441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 556786813 (or 556786807 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 36.

Adding to 131403520314441 its reverse (144413025304131), we get a palindrome (275816545618572).

The spelling of 131403520314441 in words is "one hundred thirty-one trillion, four hundred three billion, five hundred twenty million, three hundred fourteen thousand, four hundred forty-one".